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@ -0,0 +1,275 @@
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# by https://github.com/Cosmo-klara
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from __future__ import print_function
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import re
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import inflect
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import unicodedata
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# 后缀计量单位替换表
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measurement_map = {
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"m": ["meter", "meters"],
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'km': ["kilometer", "kilometers"],
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"km/h": ["kilometer per hour", "kilometers per hour"],
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"ft": ["feet", "feet"],
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"L": ["liter", "liters"],
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"tbsp": ["tablespoon", "tablespoons"],
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'tsp': ["teaspoon", "teaspoons"],
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"h": ["hour", "hours"],
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"min": ["minute", "minutes"],
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"s": ["second", "seconds"],
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"°C": ["degree celsius", "degrees celsius"],
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"°F": ["degree fahrenheit", "degrees fahrenheit"]
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}
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# 识别 12,000 类型
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_inflect = inflect.engine()
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# 转化数字序数词
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_ordinal_number_re = re.compile(r'\b([0-9]+)\. ')
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# 我听说好像对于数字正则识别其实用 \d 会好一点
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_comma_number_re = re.compile(r'([0-9][0-9\,]+[0-9])')
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# 时间识别
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_time_re = re.compile(r'\b([01]?[0-9]|2[0-3]):([0-5][0-9])\b')
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# 后缀计量单位识别
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_measurement_re = re.compile(r'\b([0-9]+(\.[0-9]+)?(m|km|km/h|ft|L|tbsp|tsp|h|min|s|°C|°F))\b')
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# 前后 £ 识别 ( 写了识别两边某一边的，但是不知道为什么失败了┭┮﹏┭┮ )
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_pounds_re_start = re.compile(r'£([0-9\.\,]*[0-9]+)')
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_pounds_re_end = re.compile(r'([0-9\.\,]*[0-9]+)£')
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# 前后 $ 识别
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_dollars_re_start = re.compile(r'\$([0-9\.\,]*[0-9]+)')
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_dollars_re_end = re.compile(r'([(0-9\.\,]*[0-9]+)\$')
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# 小数的识别
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_decimal_number_re = re.compile(r'([0-9]+\.\s*[0-9]+)')
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# 分数识别 (形式 "3/4" )
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_fraction_re = re.compile(r'([0-9]+/[0-9]+)')
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# 序数词识别
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_ordinal_re = re.compile(r'[0-9]+(st|nd|rd|th)')
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# 数字处理
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_number_re = re.compile(r'[0-9]+')
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def _convert_ordinal(m):
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"""
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标准化序数词, 例如: 1. 2. 3. 4. 5. 6.
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Examples:
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input: "1. "
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output: "1st"
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然后在后面的 _expand_ordinal, 将其转化为 first 这类的
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"""
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ordinal = _inflect.ordinal(m.group(1))
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return ordinal + ", "
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def _remove_commas(m):
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return m.group(1).replace(',', '')
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def _expand_time(m):
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"""
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将 24 小时制的时间转换为 12 小时制的时间表示方式。
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Examples:
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input: "13:00 / 4:00 / 13:30"
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output: "one o'clock p.m. / four o'clock am. / one thirty p.m."
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"""
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hours, minutes = map(int, m.group(1, 2))
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period = 'a.m.' if hours < 12 else 'p.m.'
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if hours > 12:
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hours -= 12
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hour_word = _inflect.number_to_words(hours)
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minute_word = _inflect.number_to_words(minutes) if minutes != 0 else ''
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if minutes == 0:
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return f"{hour_word} o'clock {period}"
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else:
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return f"{hour_word} {minute_word} {period}"
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def _expand_measurement(m):
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"""
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处理一些常见的测量单位后缀, 目前支持: m, km, km/h, ft, L, tbsp, tsp, h, min, s, °C, °F
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如果要拓展的话修改: _measurement_re 和 measurement_map
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"""
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sign = m.group(3)
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ptr = 1
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# 想不到怎么方便的取数字，又懒得改正则，诶，1.2 反正也是复数读法，干脆直接去掉 "."
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num = int(m.group(1).replace(sign, '').replace(".",''))
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decimal_part = m.group(2)
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# 上面判断的漏洞，比如 0.1 的情况，在这里排除了
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if decimal_part == None and num == 1:
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ptr = 0
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return m.group(1).replace(sign, " " + measurement_map[sign][ptr])
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def _expand_pounds(m):
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"""
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没找到特别规范的说明，和美元的处理一样，其实可以把两个合并在一起
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"""
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match = m.group(1)
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parts = match.split('.')
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if len(parts) > 2:
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return match + ' pounds' # Unexpected format
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pounds = int(parts[0]) if parts[0] else 0
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pence = int(parts[1].ljust(2, '0')) if len(parts) > 1 and parts[1] else 0
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if pounds and pence:
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pound_unit = 'pound' if pounds == 1 else 'pounds'
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penny_unit = 'penny' if pence == 1 else 'pence'
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return '%s %s and %s %s' % (pounds, pound_unit, pence, penny_unit)
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elif pounds:
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pound_unit = 'pound' if pounds == 1 else 'pounds'
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return '%s %s' % (pounds, pound_unit)
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elif pence:
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penny_unit = 'penny' if pence == 1 else 'pence'
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return '%s %s' % (pence, penny_unit)
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else:
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return 'zero pounds'
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def _expand_dollars(m):
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"""
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change: 美分是 100 的限值, 应该要做补零的吧
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Example:
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input: "32.3$ / $6.24"
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output: "thirty-two dollars and thirty cents" / "six dollars and twenty-four cents"
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"""
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match = m.group(1)
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parts = match.split('.')
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if len(parts) > 2:
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return match + ' dollars' # Unexpected format
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dollars = int(parts[0]) if parts[0] else 0
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cents = int(parts[1].ljust(2, '0')) if len(parts) > 1 and parts[1] else 0
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if dollars and cents:
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dollar_unit = 'dollar' if dollars == 1 else 'dollars'
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cent_unit = 'cent' if cents == 1 else 'cents'
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return '%s %s and %s %s' % (dollars, dollar_unit, cents, cent_unit)
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elif dollars:
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dollar_unit = 'dollar' if dollars == 1 else 'dollars'
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return '%s %s' % (dollars, dollar_unit)
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elif cents:
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cent_unit = 'cent' if cents == 1 else 'cents'
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return '%s %s' % (cents, cent_unit)
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else:
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return 'zero dollars'
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# 小数的处理
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def _expand_decimal_number(m):
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"""
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Example:
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input: "13.234"
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output: "thirteen point two three four"
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"""
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match = m.group(1)
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parts = match.split('.')
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words = []
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# 遍历字符串中的每个字符
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for char in parts[1]:
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if char == '.':
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words.append("point")
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else:
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words.append(char)
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return parts[0] + " point " + " ".join(words)
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# 分数的处理
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def _expend_fraction(m):
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"""
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规则1: 分子使用基数词读法, 分母用序数词读法.
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规则2: 如果分子大于 1, 在读分母的时候使用序数词复数读法.
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规则3: 当分母为2的时候, 分母读做 half, 并且当分子大于 1 的时候, half 也要用复数读法, 读为 halves.
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Examples:
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| Written | Said |
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|:---:|:---:|
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| 1/3 | one third |
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| 3/4 | three fourths |
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| 5/6 | five sixths |
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| 1/2 | one half |
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| 3/2 | three halves |
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"""
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match = m.group(0)
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numerator, denominator = map(int, match.split('/'))
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numerator_part = _inflect.number_to_words(numerator)
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if denominator == 2:
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if numerator == 1:
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denominator_part = 'half'
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else:
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denominator_part = 'halves'
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elif denominator == 1:
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return f'{numerator_part}'
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else:
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denominator_part = _inflect.ordinal(_inflect.number_to_words(denominator))
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if numerator > 1:
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denominator_part += 's'
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return f'{numerator_part} {denominator_part}'
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def _expand_ordinal(m):
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return _inflect.number_to_words(m.group(0))
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def _expand_number(m):
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num = int(m.group(0))
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if num > 1000 and num < 3000:
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if num == 2000:
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return 'two thousand'
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elif num > 2000 and num < 2010:
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return 'two thousand ' + _inflect.number_to_words(num % 100)
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elif num % 100 == 0:
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return _inflect.number_to_words(num // 100) + ' hundred'
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else:
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return _inflect.number_to_words(num, andword='', zero='oh', group=2).replace(', ', ' ')
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else:
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return _inflect.number_to_words(num, andword='')
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def normalize(text):
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"""
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!!! 所有的处理都需要正确的输入 !!!
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可以添加新的处理，只需要添加正则表达式和对应的处理函数即可
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"""
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text = re.sub(_ordinal_number_re, _convert_ordinal, text)
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text = re.sub(r'(?<!\d)-|-(?!\d)', ' minus ', text)
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text = re.sub(_comma_number_re, _remove_commas, text)
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text = re.sub(_time_re, _expand_time, text)
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text = re.sub(_measurement_re, _expand_measurement, text)
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text = re.sub(_pounds_re_start, _expand_pounds, text)
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text = re.sub(_pounds_re_end, _expand_pounds, text)
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text = re.sub(_dollars_re_start, _expand_dollars, text)
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text = re.sub(_dollars_re_end, _expand_dollars, text)
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text = re.sub(_decimal_number_re, _expand_decimal_number, text)
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text = re.sub(_fraction_re, _expend_fraction, text)
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text = re.sub(_ordinal_re, _expand_ordinal, text)
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text = re.sub(_number_re, _expand_number, text)
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text = ''.join(char for char in unicodedata.normalize('NFD', text)
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if unicodedata.category(char) != 'Mn') # Strip accents
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text = re.sub("%", " percent", text)
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text = re.sub("[^ A-Za-z'.,?!\-]", "", text)
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text = re.sub(r"(?i)i\.e\.", "that is", text)
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text = re.sub(r"(?i)e\.g\.", "for example", text)
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# 增加纯大写单词拆分
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text = re.sub(r'(?<!^)(?<![\s])([A-Z])', r' \1', text)
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return text
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if __name__ == '__main__':
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# 我觉得其实可以把切分结果展示出来（只读，或者修改不影响传给TTS的实际text）
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# 然后让用户确认后再输入给 TTS，可以让用户检查自己有没有不标准的输入
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print(normalize("1. test ordinal number 1st"))
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print(normalize("32.3$, $6.24, 1.1£, £7.14."))
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print(normalize("3/23, 1/2, 3/2, 1/3, 6/1"))
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print(normalize("1st, 22nd"))
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print(normalize("a test 20h, 1.2s, 1L, 0.1km"))
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print(normalize("a test of time 4:00, 13:00, 13:30"))
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print(normalize("a test of temperature 4°F, 23°C, -19°C"))
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KamioRinn
6 months ago
committed by
GitHub